member function on a non-object

Det kommer an på hvad din db.php laver. Måske

  $db = new ....noget...;

$db = mysql_select_db("$database_name", $connection)
    or die("Couldn't select database.");

$_COOKIE['username'] skulle jeg mene??

$sql = "SELECT * FROM users WHERE username='$_COOKIE['username']'";

ldanielsen:
den giver denne fejl:
Parse error: parse error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /customers/explosif.dk/explosif.dk/httpd.www/user_edit_profile.php on line 7

Hvis der står
    $db = mysql_select_db("$database_name", $connection) or die("Couldn't select database.");
i din db.php skal du bare
    $result = mysql_query($sql) or die(mysql_error());

Query was empty ??? Hmm, det giver jo ingen mening!
Måske noget i denne stil:
$result = mysql_result($sql) or die(mysql_error());
Men så får jeg:
Warning: Wrong parameter count for mysql_result()

der er vel ingen, der siger du skal bruge mysql_result.
"Query was empty" er fordi $sql er tom. Må vi se din kode?

db.php
<?
$to_secs = 120;

$dbhost = 'localhost';
$dbusername = 'explosif_dk';
$dbpasswd = 'XXXXXX';
$database_name = 'explosif_dk';
$sitepath = "http://www.explosif.dk/_test/";                                                                               
$sitename = "explosif.dk";
$adminemail = "xxxx@explosif.dk";

$connection = mysql_pconnect("$dbhost","$dbusername","$dbpasswd")
    or die ("Couldn't connect to server.");

$db = mysql_select_db("$database_name", $connection)
    or die("Couldn't select database.");

?>

user_edit_profile.php: (Hele svineriet)

<?php
include('db.php');
include('common.php');

if($_COOKIE['loged'] == 'yes') { //if1
  if($_COOKIE['user_level'] == '2') { //if2
      $sql = "SELECT * FROM users WHERE username='$_COOKIE[username]'";
      $result = $db->query($sql);

      while($row = $db->fetch($result)) {
            $userid = $row['userid'];
            $email_address = $row['email_address'];
            $username = $row['username'];
            $f_name = $row['f_name'];
            $l_name = $row['l_name'];
            $decrypted_pass = base64_decode($row['decrypted_pass']);
?>
<link href="site_files/css/clean_css_v2.css" rel="stylesheet" type="text/css">

<table width="100%"  border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td valign="top"><table width="600"  border="0" cellpadding="0" cellspacing="0" class="nws_bar">
        <tr>
          <td width="566"><div align="center">Login</div></td>
        </tr>
      </table>
        <table width="600" border="0" cellpadding="0" cellspacing="0" bgcolor="#585858" class="nws_border">
          <form name=form1 method=post action=register.php>
            <tr>
              <td width="40"><div align="center"><img src="site_files/gfx/pil.gif" width="9" height="9"></div></td>
              <td width="100">First Name</td>
              <td width="460"><input name=first_name type=text class="input_field" id=\"first_name\" value=\"$first_name\"></td>
            </tr>
          </form>
        </table>
        <table width="600" border="0" cellpadding="0" cellspacing="0" bgcolor="#666666" class="nws_border">
          <tr>
            <td width="40"><div align="center"><img src="site_files/gfx/pil.gif" width="9" height="9"></div></td>
            <td width="100">Last Name</td>
            <td width="460"><input name=last_name type=text class="input_field" id=\"last_name\" value=\"$last_name\"></td>
          </tr>
        </table>
        <table width="600" border="0" cellpadding="0" cellspacing="0" bgcolor="#585858" class="nws_border">
          <tr>
            <td width="40"><div align="center"><img src="site_files/gfx/pil.gif" width="9" height="9"></div></td>
            <td width="100">Email Address</td>
            <td width="460"><input name=email_address type=text class="input_field" id=\"email_address\" value=\"$email_address\"></td>
          </tr>
        </table>
        <table width="600" border="0" cellpadding="0" cellspacing="0" bgcolor="#666666" class="nws_border">
          <tr>
            <td>&nbsp;</td>
            <td>Username</td>
            <td><input name=username type=text class="input_field" id=\"username\" value=\"$username\"></td>
          </tr>
          <tr>
            <td width="40"><div align="center"><img src="site_files/gfx/pil.gif" width="9" height="9"></div></td>
            <td width="100">Password</td>
            <td width="460"><input name=password type=text class="input_field" id=\"decrypted_pass\" value=\"$decrypted_pass\"></td>
          </tr>
        </table>
        <table width="600" border="0" cellpadding="0" cellspacing="0" bgcolor="#666666" class="nws_border">
          <tr>
            <td width="40" valign="top"><div align="center"></div></td>
            <td width="100" valign="top">Information about you:</td>
            <td width="460"><textarea name=info cols="40" rows="5" class="textfield" id=info></textarea></td>
          </tr>
        </table>
        <table width="600" border="0" cellpadding="0" cellspacing="0" bgcolor="#585858" class="nws_border">
          <tr>
            <td width="40">&nbsp;</td>
            <td width="100">&nbsp;</td>
            <td width="460"><input name=Submit type=submit class="button_site" value=Update></td>
          </tr>
        </table>
        <div align="left"></div>
        <div align="center"></div></td>
  </tr>
</table>

<? 
}   
  } else {
      echo "<font class=\"text\">You dont have permission to view this page.</font>";
        exit();
  }
} else {
      echo "<font class=\"text\">You are not logged in. Please do so <a href=\"../login.php\">Here</a>.</font>";
          exit();
}
?>

Men det er jo den oprindelige, der ikke virker pga $result = $db->query($sql);
ikke? Du får en fejl "Query was empty", som jeg troede var den vi skulle have rettet.

Sætter jeg $result = mysql_query($sql) or die(mysql_error());
ind istedet for: $result = $db->query($sql);
Får jeg igen denne:
Call to a member function on a non-object in

Ja, for du har samme problem i
      while($row = $db->fetch($result)) {
som skal være
      while($row = mysql_fetch_array($result)) {
Det hjælper ikke meget at skrive ukritsk af fra eksempler uden at vide
hvad der sker ;)

Du mener med andre ord, at man skal kravle før man kan gå? :)
Tjooo, men anyways.. så fungerer det for mig nu! Tusinde tak! HUSK SVAR :D

Mnjah, det var da sådan jeg lærte at gå.
Men ellers tak, jeg samler slet ikke på point.

.