Loade fra mapper.

.jpg billeder regner jeg med:

$pics = glob( '/gfx/baggrunde/*.jpg' );
$toj = glob( '/man/toj/*.jpg' );
$hovede = glob( '/man/hovede/*.jpg' );
$sko = glob( '/man/sko/*.jpg' );
$talebobler = glob( '/talebobler/*.jpg' );
$pics = array_merge( $pics, $toj, $hovede, $sko, $talebobler );

echo '<script type="text/javascript">';
$n = 0;
foreach ( $pics as $pic )
{
  echo 'var i' . $n . " = new Image();\n";
  echo 'i' . $n . ".src = '$pic';\n";
}
echo '</script>';

Ikke et array, men jeg regner med du bare vil preloade billederne :P

der er også .gif billedere? :S

kan man lave en som både loader .gif og .jpg?

aah..
kan man dette tror du?
$pics = glob( '/gfx/baggrunde/*.jpg' );
$toj = glob( '/man/toj/*.gif' );
$hovede = glob( '/man/hovede/*.gif' );
$sko = glob( '/man/sko/*.gif' );
$talebobler = glob( '/talebobler/*.gif' );
$pics = array_merge( $pics, $toj, $hovede, $sko, $talebobler );

Du kan jo gøre det samme med *.gif

hos mig siger den:


<script type="text/javascript">var i0 = new Image();
i0.src = '/gfx/baggrunde/1.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/2.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/3.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/4.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/5.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/6.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/7.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/8.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/9.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/Banken.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/Parken.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/Postoffice.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/admin.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/bix.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/lej.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/relad.jpg';
var i0 = new Image();
i0.src = '/gfx/baggrunde/standard.jpg';
var i0 = new Image();
i0.src = '/man/toj/1.gif';
var i0 = new Image();
i0.src = '/man/toj/2.gif';
var i0 = new Image();
i0.src = '/man/toj/3.gif';
var i0 = new Image();
i0.src = '/man/toj/4.gif';
var i0 = new Image();
i0.src = '/man/toj/8.gif';
var i0 = new Image();
i0.src = '/man/toj/admin.gif';
var i0 = new Image();
i0.src = '/man/toj/orange.gif';
var i0 = new Image();
i0.src = '/man/toj/qyran.gif';
var i0 = new Image();
i0.src = '/man/toj/qyrsko.gif';
var i0 = new Image();
i0.src = '/man/toj/stribet.gif';
var i0 = new Image();
i0.src = '/man/toj/strik.gif';
var i0 = new Image();
i0.src = '/man/toj/tehnet.gif';
var i0 = new Image();
i0.src = '/man/hovede/1.gif';
var i0 = new Image();
i0.src = '/man/hovede/2.gif';
var i0 = new Image();
i0.src = '/man/hovede/admin.gif';
var i0 = new Image();
i0.src = '/man/hovede/face.gif';
var i0 = new Image();
i0.src = '/man/hovede/faceII.gif';
var i0 = new Image();
i0.src = '/man/hovede/fagget.gif';
var i0 = new Image();
i0.src = '/man/hovede/junkie.gif';
var i0 = new Image();
i0.src = '/man/sko/1.gif';
var i0 = new Image();
i0.src = '/man/sko/2.gif';
var i0 = new Image();
i0.src = '/man/sko/3.gif';
var i0 = new Image();
i0.src = '/man/sko/admin.gif';
var i0 = new Image();
i0.src = '/man/sko/qyrsko.gif';
var i0 = new Image();
i0.src = '/talebobler/bund-hojre.gif';
var i0 = new Image();
i0.src = '/talebobler/bund-venstre.gif';
var i0 = new Image();
i0.src = '/talebobler/bund.gif';
var i0 = new Image();
i0.src = '/talebobler/hojre.gif';
var i0 = new Image();
i0.src = '/talebobler/top-hojre.gif';
var i0 = new Image();
i0.src = '/talebobler/top-venstre.gif';
var i0 = new Image();
i0.src = '/talebobler/top.gif';
var i0 = new Image();
i0.src = '/talebobler/venstre.gif';
</script>


Skal hver i0 ikke hedder noget forskelligt?

hov, jo:

foreach ( $pics as $pic )
{
  echo 'var i' . $n . " = new Image();\n";
  echo 'i' . $n . ".src = '$pic';\n";
}

skulle have været:

foreach ( $pics as $pic )
{
  echo 'var i' . $n . " = new Image();\n";
  echo 'i' . $n . ".src = '$pic';\n";
  $n++;
}