php og mysql

Du kan lave en checkbox:
<?PHP
//connection
$guest = array();
if(isset($_POST['Submit'])) {
  foreach($guest AS $val) {
      $update_sql = "UPDATE tilmeldte SET checked = '".$val."'";
      $update_query = mysql_query($update_sql);
  }
}

$sql = "SELECT id, navn, checked FROM tilmeldte";
$query = mysql_query($sql);
echo "<form action=\"\" method=\"post\">
while($r = mysql_fetch_array($query)) {
if($r['checked'])
  $selected = " checked";
else
  $selected = "";

echo "Bruger: ".$r['navn']." <input type=\"\" name=\"guest[]\" value=\"".$r['id']."\"".$selected." /><br />\n";
}
echo "<input type=\"submit\" name=\"Submit\" value=\"Gem\" />";
?>
</form>

Dette er mit bud. Håber det kan hjælpe dig

Tror dette virker:
<?
if(isset($_POST['id'])){
    $id = $_POST['id'];
    if(is_array($id)){
        $id2 = array();
        foreach($id as $value){
            if(is_numeric($value)){
                $id2[] = $value;
            }else{
                echo"Der skete en fejl";
            }
        }
        $id = implode(",", $id2);
        $sql = "UPDATE dintabel SET godkendt='ja' WHERE id IN ($id)";
        mysql_query($sql);
              }
  echo"Alle de afkrydset blev godkendt";

$result = mysql_query("SELECT * FROM dintabel order by navn DESC");
while($row = mysql_fetch_array($result)) {  $color = ($i%2) ? "#1e1e1e" : "#1a1a1a" ; $i++;
echo"
<table border=0 width=100% cellspacing=0 cellpadding=0 height=12>
<tr>
<td style='background-color: $color' width=30% valign=top height=12><font size=1 face=Verdana color=#FFFFFF>$row[navn]</font></td>
<td style='background-color: $color' width=30% valign=top height=12><font size=1 face=Verdana color=#FFFFFF>$row[godkend]</font></td>
<td style='background-color: $color' width=20% valign=top height=12><font size=1 face=Verdana color=#FFFFFF>$row[alder]</font></td>
<td style='background-color: $color' width=20% valign=top height=12><font size=1 face=Verdana><input type=checkbox name=id[] value=$row[id]></font></td>
</tr>
</table>
\n";
}
?>