upload spørgsmål
Hej er der en måde at få det her script til ikke at overskrive et billede på serveren hvis det har samme navn som det man uploader, jeg mener hvis der allerede ligger et billede kaldet "bil" i mappen photo på serveren og jeg uploader et andet billede også kaldet "bil" til mappen.Hvis ikke kan man så så lave en funktion "tilføjelse i script" der fortæller uploader at der allerede er et billede på serveren med det navn.
Takker for hjælpen...
upload script
<html>
<head>
<title>Upload File To MySQL Database</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<style type="text/css">
<!--
.box {
font-family: Arial, Helvetica, sans-serif;
font-size: 12px;
border: 1px solid #000000;
}
-->
</style>
</head>
<body>
<?
// you can change this to any directory you want
// as long as php can write to it
$uploadDir = '../photo/';
if(isset($_POST['upload']))
{
$fileName = $_FILES['userfile']['name'];
$tmpName = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];
// the files will be saved in filePath
$filePath = $uploadDir . $fileName;
// move the files to the specified directory
// if the upload directory is not writable or
// something else went wrong $result will be false
$result = move_uploaded_file($tmpName, $filePath);
if (!$result) {
echo "Error uploading file";
exit;
}
include 'library/config.php';
include 'library/opendb.php';
if(!get_magic_quotes_gpc())
{
$fileName = addslashes($fileName);
$filePath = addslashes($filePath);
}
$query = "INSERT INTO upload2 (name, size, type, path ) ".
"VALUES ('$fileName', '$fileSize', '$fileType', '$filePath')";
mysql_query($query) or die('Error, query failed : ' . mysql_error());
include 'library/closedb.php';
echo "<br>File uploaded<br>";
}
?>
<form action="" method="post" enctype="multipart/form-data" name="uploadform">
<table width="350" border="0" cellpadding="1" cellspacing="1" class="box">
<tr>
<td width="246"><input type="hidden" name="MAX_FILE_SIZE" value="2000000"><input name="userfile" type="file" class="box" id="userfile">
</td>
<td width="80"><input name="upload" type="submit" class="box" id="upload" value=" Upload "></td>
</tr>
</table>
</form>
</body>
</html>
