online lige nu?

<?php
$connection = mysql_pconnect("host", "user", "pass");
mysql_select_db("database");

$ip = getenv(REMOTE_ADDR);

$tid = date("Y-m-d H:i:s", (time()-600));
$delete = "DELETE FROM online WHERE tid < '$tid'";
mysql_query($delete);

$tjek = mysql_query("SELECT * FROM online where ip='$ip'");
if(mysql_num_rows($tjek) == 0) {

$ind = "INSERT INTO online (tid, ip) VALUES (now(),'$ip')";
mysql_query($ind);

}else{
$update = "update online set tid=now() where ip='$ip'";
mysql_query($update);
}

$online = mysql_query("SELECT * FROM online");

echo "Der er lige nu ".mysql_num_rows($online).";

mysql_close($connection);
?>

Din tabel skal så have et id, tip og ip felt.

Lige rettet lidt til:

<?php
$connection = mysql_pconnect("host", "user", "pass");
mysql_select_db("database");
$ip = getenv(REMOTE_ADDR);
$tid = date("Y-m-d H:i:s", (time()-600));
mysql_query("DELETE FROM online WHERE tid < '$tid'");

$tjek = mysql_query("SELECT * FROM online where ip='$ip'");
if(mysql_num_rows($tjek) == 0) {
    mysql_query("INSERT INTO online (tid, ip) VALUES (now(),'$ip')");
} else {
    mysql_query("update online set tid=now() where ip='$ip'");
}
$online = mysql_query("SELECT * FROM online");
echo "Der er lige nu ".mysql_num_rows($online)."online";
mysql_close($connection);
?>

thanx :D

$online = mysql_query("SELECT COUNT(*) AS antal FROM online");
echo 'Der er lige nu '.mysql_result($online,0).' online';