Hjælp til to koloner

<?
$cells = 2;
$cellcount = 1;

$sql = 'SELECT sti FROM `fest_pics` WHERE fest_id='.$_GET['id'].' LIMIT 0,10';

$result = mysql_query($sql) or die(mysql_error());

while ($row = mysql_fetch_array($result)) {

    $sti = $row["sti"];

    echo "<td><a href=\"java script:popup('$sti')\"><img src=\"$sti\" border=\"0\" height=\"75\" width=\"100\"></a><br> <hr color=\"#cccccc\"></td>";
    if ($cellcount == $cells) {
        $cellcount = 0;
        echo "</tr><tr>";
    }
    $cellcount++;
  }
 
while ($cellcount <= $cells) {
    echo '<td></td>';
    $cellcount++;
}

echo "</tr></table>";
?>

<table><tr>
<?php
$cells = 2; // Antal celler ved siden af hinanden
$cellcount = 1;

$result = mysql_query('SELECT sti FROM `fest_pics` WHERE fest_id='.$_GET['id'].' LIMIT 0,10') or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
    $sti = $row['sti'];
    echo "<td><a href=\"java script: popup('$sti')\"><img src=\"$sti\" border=\"0\" height=\"75\" width=\"100\"></a></td>";
    if ($cellcount == $cells) {
        $cellcount = 0;
        echo "</tr><tr>";
    }
    $cellcount++;
}

// Udfylder de tommme celler
while ($cellcount <= $cells) {
    echo "<td width=\"$tdwidth\">&nbsp;</td>";
    $cellcount++;
}
?>
</tr></table>

;o)

Eller prøv denne:

<?php
$cells = 2;
$cellcount = 1;

$result = mysql_query("SELECT sti FROM fest_pics WHERE fest_id='$_GET[id]' LIMIT 0,10") or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
    echo "<td><a href=\"java script:popup('$row[sti]')\"><img src=\"$row[sti]\" border=\"0\" height=\"75\" width=\"100\"></a><br> <hr color=\"#cccccc\"></td>";
    if ($cellcount == $cells) {
        $cellcount = 0;
        echo "</tr><tr>";
    }
    $cellcount++;
  }
 
while ($cellcount <= $cells) {
    echo "<td></td>";
    $cellcount++;
}

echo "</tr></table>";
?>

Sådan...

<?php
echo "<table align="left" border="0"><tr>";
$cells = 2;
$cellcount = 1;

$result = mysql_query("SELECT sti FROM fest_pics WHERE fest_id='$_GET[id]' LIMIT 0,10") or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
    echo "<td><a href=\"java script:popup('$row[sti]')\"><img src=\"$row[sti]\" border=\"0\" height=\"75\" width=\"100\"></a><br> <hr color=\"#cccccc\"></td>";
    if ($cellcount == $cells) {
        $cellcount = 0;
        echo "</tr><tr>";
    }
    $cellcount++;
  }
 
while ($cellcount <= $cells) {
    echo "<td></td>";
    $cellcount++;
}

echo "</tr></table>";
?>

puha i er jo ikke mere end 26 sek i mellem *G*
i burde jo dele vil jeg mene, så Schaefner smid et svar

<table><tr>
<?php
$cells = 2; // Antal celler ved siden af hinanden
$cellcount = 1;

$result = mysql_query('SELECT sti FROM `fest_pics` WHERE fest_id='.$_GET['id'].' LIMIT 0,10') or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
    $sti = $row['sti'];
    echo "<td><a href=\"java script: popup('$sti')\"><img src=\"$sti\" border=\"0\" height=\"75\" width=\"100\"></a></td>";
    if ($cellcount == $cells) {
        $cellcount = 0;
        echo '</tr><tr>';
    }
    $cellcount++;
}

// Udfylder de tommme celler
while ($cellcount <= $cells) {
    echo '<td></td>';
    $cellcount++;
}
?>
</tr></table>

Dur den?

schaefner tror du kan hjælpe mig med dette problem? -> http://www.eksperten.dk/spm/418342

jeres første forslag virker fint..

ok...

Mit første forslag manglet der bare dette i toppen: echo "<table align="left" border="0"><tr>";

Zorg_86 den på siden fik den bare ikke  taget med i spørgsmålet ;o)

Men jeg takker jer begge to... ;o)

takker..