Subscript out of range

Hej

Jeg har nu forsøgt mig med en del forskellige scripts til at uploade billeder med, men havde ikke kunne få nogen af dem til at fungere, på nær et. Det fungere som det skal på min egen com, men efter at jeg har uplodet det til mit webhotel, får jeg følgende fejl:

Subscript out of range: '[number: 0]'

/FilePost2.asp, line 59

scriptet har i her (det er temmelig langt):

<%
response.buffer = true

if Session("login") <> "loged_in" then
    Response.Redirect("admin_login.asp")
else
'Adjust this depending on the size of the files you'll
'be expecting; longer timeout for larger files!
Server.ScriptTimeout = 5400

Const ForWriting = 2
Const TristateTrue = -1
CrLf = Chr(13) & Chr(10)

'This function retreives a field's name
Function GetFieldName(infoStr)
    sPos = InStr(infoStr, "name=")
    EndPos = InStr(sPos + 6, infoStr, Chr(34) & ";")
    If EndPos = 0 Then
        EndPos = inStr(sPos + 6, infoStr, Chr(34))
    End If
    GetFieldName = Mid(infoStr, sPos + 6, endPos - _
        (sPos + 6))
End Function

'This function retreives a file field's filename
Function GetFileName(infoStr)
    sPos = InStr(infoStr, "filename=")
    EndPos = InStr(infoStr, Chr(34) & CrLf)
    GetFileName = Mid(infoStr, sPos + 10, EndPos - _
        (sPos + 10))
End Function

'This function retreives a file field's MIME type
Function GetFileType(infoStr)
    sPos = InStr(infoStr, "Content-Type: ")
    GetFileType = Mid(infoStr, sPos + 14)
End Function

'Yank the file (and anything else) that was posted
PostData = ""
Dim biData
biData = Request.BinaryRead(Request.TotalBytes)
'Careful! It's binary! So, let's change it into
'something a bit more manageable.
For nIndex = 1 to LenB(biData)
    PostData = PostData & Chr(AscB(MidB(biData,nIndex,1)))
Next

'Having used BinaryRead, the Request.Form collection is
'no longer available to us. So, we have to parse the
'request variables ourselves!
'First, let's find that encoding type!
ContentType = Request.ServerVariables( _
    "HTTP_CONTENT_TYPE")
ctArray = Split(ContentType, ";")
'File posts only work well when the encoding is
'"multipart/form-data", so let's check for that!
If Trim(ctArray(0)) = "multipart/form-data" Then
    ErrMsg = ""
    ' grab the form boundary...
    bArray = Split(Trim(ctArray(1)), "=")
    Boundary = Trim(bArray(1))
    'Now use that to split up all the variables!
    FormData = Split(PostData, Boundary)
    'Extract the information for each variable and its data
    Dim myRequest, myRequestFiles(9, 3)
    Set myRequest = CreateObject("Scripting.Dictionary")
    FileCount = 0
    For x = 0 to UBound(FormData)
        'Two CrLfs mark the end of the information about
        'this field; everything after that is the value
        InfoEnd = InStr(FormData(x), CrLf & CrLf)
        If InfoEnd > 0 Then
            'Get info for this field, minus stuff at the end
            varInfo = Mid(FormData(x), 3, InfoEnd - 3)
            'Get value for this field, being sure to skip
            'CrLf pairs at the start and the CrLf at the end
            varValue = Mid(FormData(x), InfoEnd + 4, _
                Len(FormData(x)) - InfoEnd - 7)
            'Is this a file?
            If (InStr(varInfo, "filename=") > 0) Then
                'Place it into our files array
                '(While this supports more than one file
                'uploaded at a time we only consider the
                'single file case in this example)
                myRequestFiles(FileCount, 0) = GetFieldName( _
                    varInfo)
                myRequestFiles(FileCount, 1) = varValue
                myRequestFiles(FileCount, 2) = GetFileName( _
                    varInfo)
                myRequestFiles(FileCount, 3) = GetFileType( _
                    varInfo)
                FileCount = FileCount + 1
            Else
                'It's a regular field
                myRequest.add GetFieldName(varInfo), varValue
            End If
        End If
    Next
Else
    ErrMsg = "Wrong encoding type!"
End If

'Save the actual posted file
'If supporting more than one file, turn this into a loop!

Set lf = server.createObject("Scripting.FileSystemObject")
If myRequest("filename") = "original" Then
    'Use the filename that came with the file
    'At this point, you need to determine what sort of
    'client sent the file. Macintoshes only send the file
    'name, with no path information, while Windows clients
    'send the entire path of the file that was selected
    BrowserType = UCase(Request.ServerVariables( _
        "HTTP_USER_AGENT"))
    If (InStr(BrowserType, "WIN") > 0) Then
        'It's Windows; yank the filename off the end!
        sPos = InStrRev(myRequestFiles(0, 2), "\")
        fName = Mid(myRequestFiles(0, 2), sPos + 1)
    End If
    If (InStr(BrowserType, "MAC") > 0) Then
        'It's a Mac. Simple.
        '(Mac filenames can contain characters that are
        'illegal under Windows, so look out for that!)
        fName = myRequestFiles(0, 2)
    End If
    'If your upload path is different, set that here
    FilePath = "../images/" & fName
Else
    'Use the user-specified filename instead
    'If your upload path is different, set that here
    FilePath = "../images/" & myRequest("userSpecifiedName")
End If
SavePath = Server.MapPath(FilePath)
Set SaveFile = lf.CreateTextFile(SavePath, True)
SaveFile.Write(myRequestFiles(0, 1))
SaveFile.Close

'IIS may hang if you don't explicitly return SOMETHING.
'So, redirect to another page or provide some kind of
'feedback below...
%>
<html>
<body>
<% If ErrMsg = "" Then %>
    Billedet er nu uploadet til mappen "Images"<br><br>
    <a href="default.asp">Klik her</a> for at vende tilbage
<% Else %>
    <%= ErrMsg %>
<% End If %>
</body>
</html>
<% end if %>

linie 59 er hvor der står:

If Trim(ctArray(0)) = "multipart/form-data" Then

Mvh
software