Avatar billede tahoo Nybegynder
17. januar 2004 - 21:07 Der er 1 kommentar og
1 løsning

upload script

Hej Jeg har dette script :


<%    @EnableSessionState    = False %>
<%    Option Explicit %>
<%    Response.Expires    = 0 %>
<%

    Dim UPLOAD_PATH
        UPLOAD_PATH    = Server.MapPath("/upload")

    Dim g_oFso, g_oFolder, g_oFile
        Set g_oFso    = Server.CreateObject("Scripting.FileSystemObject")
        Set g_oFolder    = g_oFso.getFolder(UPLOAD_PATH)

    If (Request.ServerVariables("REQUEST_METHOD") = "POST") Then
        Dim g_oUpload
            Set g_oUpload    = get_upload_files()

        Dim fpos, fcontent
            fcontent    = g_oUpload("upload").Item("content")
        Set g_oFile    = g_oFso.CreateTextFile(UPLOAD_PATH & "\" & extract_filename(g_oUpload("upload").Item("filename")))
        For fpos = 1 to LenB(fcontent)
            g_oFile.Write chr(AscB(MidB(fcontent, fpos, 1)))
        Next
        g_oFile.Close: Set g_oFile    = Nothing

        Response.Redirect Request.ServerVariables("SCRIPT_NAME")
    End If

    Response.Write "<html><body><table>"
    Response.Write "<tr><td><hr></td></tr>"
    For Each g_oFile In g_oFolder.Files
        Response.Write "<tr><td>" & "<a href=delete.asp?id=" & g_oFile.Name & ">Slet</a> - " & "<a href=""../upload/" & g_oFile.Name & """>" & g_oFile.name & "</a></td></tr>"
    Next
    Response.Write "<tr><td><hr></td></tr>"
    Response.Write "<tr><td align=""right""><form name=""frmUpload"" method=""post"" enctype=""multipart/form-data"" action=""" & Request.ServerVariables("SCRIPT_NAME") & """>"
    Response.Write "<input type=""file"" name=""upload""> &nbsp; <input type=""submit"" value=""upload""></td></tr>"
    Response.Write "</table></body></html>"

%>
<%
    Function get_upload_files()
        Dim    upload_object, request_binaries
        Dim position_start, position_end
        Dim boundary, boundary_pos

        Set upload_object    = Server.CreateObject("Scripting.Dictionary")
        request_binaries    = Request.BinaryRead(Request.TotalBytes)
        position_start        = 1
        position_end        = InstrB(position_start, request_binaries, get_byte_string(chr(13)))
        boundary            = MidB(request_binaries, position_start, (position_end - position_start))
        boundary_pos        = InstrB(1, request_binaries, boundary)

        Do Until (boundary_pos = InstrB(request_binaries, boundary & get_byte_string("--")))
            If Not(Response.IsClientConnected) Then Response.End

            Dim name, pos_file

            position_start    = (InstrB(InstrB(boundary_pos, request_binaries, get_byte_string("Content-Disposition")), request_binaries, get_byte_string("name=")) + 6)
            position_end    = InstrB(position_start, request_binaries, get_byte_string(chr(34)))

            name            = get_string(MidB(request_binaries, position_start, (position_end - position_start)))
            pos_file        = InstrB(boundary_pos, request_binaries, get_byte_string("filename="))

            If  ((pos_file <> 0) AND (pos_file < InstrB(position_end, request_binaries, boundary))) Then
                upload_object.Add name, Server.CreateObject("Scripting.Dictionary")

                position_start    = (pos_file + 10)
                position_end    = InstrB(position_start, request_binaries, get_byte_string(chr(34)))
                upload_object.item(name).Add "filename", get_string(MidB(request_binaries, position_start, (position_end - position_start)))

                position_start    = (InstrB(position_end, request_binaries, get_byte_string("Content-Type:")) + 14)
                position_end    = InstrB(position_start, request_binaries, get_byte_string(chr(13)))
                upload_object.item(name).Add "content-type", get_string(MidB(request_binaries, position_start, (position_end - position_start)))

                position_start    = (position_end + 4)
                position_end    = InstrB(position_start, request_binaries, boundary) - 2
                upload_object.item(name).Add "size", ((position_end - position_start))
                upload_object.item(name).Add "content", MidB(request_binaries, position_start, (position_end - position_start))
            End If
            boundary_pos    = InstrB(boundary_pos + LenB(boundary), request_binaries, boundary)
        Loop

        Set get_upload_files = upload_object
    End Function

    Function get_byte_string(str)
        Dim cnt
        For cnt = 1 to Len(str)
            get_byte_string    = get_byte_string & chrB(AscB(Mid(str, cnt, 1)))
        Next
    End Function

    Function get_string(str)
        Dim cnt
        For cnt = 1 to LenB(str)
            get_string    = get_string & chr(AscB(MidB(str, cnt, 1)))
        Next
    End Function

    Function extract_filename(filename)
        extract_filename    = Right(filename, Len(filename) - InStrRev(filename, "\", -1, 1))
    End Function
   
response.write "<a href=logoff.asp>Log af</a>"
%>


Jeg ønsker så at indsætte dette i toppen af den, så jeg kan password beskytte den..:

<%
If Session("login") <> "JA" Then
  Response.Redirect "index.asp"
End If
%>

Men hvis jeg gør dette går det galt og den kommer med denne fejl..
:
Active Server Pages error 'ASP 0140'

Page Command Out Of Order

/upload.asp, line 7

The @ command must be the first command within the Active Server Page.



Hvordan kan man klare det ?
Avatar billede tahoo Nybegynder
17. januar 2004 - 21:14 #1
jg
Avatar billede tahoo Nybegynder
17. januar 2004 - 21:40 #2
hov kom til at lave en fejl... - laver lige spørgsmål igen... :)
Avatar billede Ny bruger Nybegynder

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