I dette særtema ser vi på, hvordan cloud og AI bliver fundamentet for virksomhedernes digitale forretning, og hvordan de nye muligheder for automatisering og forretningsværdi kan udnyttes uden at miste overblik, sikkerhed og menneskelig kontrol.
<html> <body> <% 'Her skal dit array ind, som test er det bare en flok forskille ord: ordArr = Split("a1,b1,c1,a2,a8,a4,b4,b3,c6,c4,a3,a5,a7,b7,c7,b6,c6,c5,b5",",")
ordArr = Sorter(ordArr) %> <table width="100%"> <% ordPrRow = 0 maxPrRow = 4 firstChar="" for i = lbound(ordArr) to ubound(ordArr) if firstChar <> ucase(left(ordArr(i),1)) then if ordPrRow > 0 then Response.Write "</tr>" ordPrRow = 0 end if firstChar = ucase(left(ordArr(i),1)) Response.Write "<tr><td colspan=""" & maxPrRow & """>" & firstChar & "</td></tr>" end if if ordPrRow = 0 then Response.Write "<tr>"
Response.Write "<td>" & ordArr(i) & "</td>"
ordPrRow = ordPrRow + 1 if ordPrRow = maxPrRow then Response.Write "</tr>" ordPrRow = 0 end if Next if ordPrRow > 0 then Response.Write "</tr>" %> </table>
</body> </html>
<% Function Sorter(ByVal tabel) Dim blnContinue, i, varFirst, varSecond blnContinue = True Do Until blnContinue = False blnContinue = False For i = 0 to UBound(tabel) If i = UBound(tabel) Then Exit For Arr = Split(tabel(i),".") tmp1 = arr(0) if isnumeric(tmp1) then tmp1 = Int(tmp1) Arr = Split(tabel(i+1),".") tmp2 = arr(0) if isnumeric(tmp2) then tmp2 = Int(tmp2) If tmp1 > tmp2 Then varFirst = tabel(i) varSecond = tabel(i+1) tabel(i) = varSecond tabel(i+1) = varFirst blnContinue = True End If Next Loop Sorter = tabel End Function %>
Mangler er mellemrum fra hvor A slutter til hvor B begynder så prøv at rette:
if firstChar <> ucase(left(ordArr(i),1)) then if ordPrRow > 0 then Response.Write "</tr>" ordPrRow = 0 end if firstChar = ucase(left(ordArr(i),1)) Response.Write "<tr><td colspan=""" & maxPrRow & """>" & firstChar & "</td></tr>" end if
Til dette:
if firstChar <> ucase(left(ordArr(i),1)) then if ordPrRow > 0 then Response.Write "</tr>" ordPrRow = 0 end if if firstChar <> "" then Response.Write "<tr><td colspan=""" & maxPrRow & """> </td></tr>" firstChar = ucase(left(ordArr(i),1)) Response.Write "<tr><td colspan=""" & maxPrRow & """>" & firstChar & "</td></tr>" end if
Det kan gøres sådan her. Hvis antallet af ord for et bogstav er imellem 3 og 9 bliver det vise i enten 3 eller 4 kolonner, da man er nød til at finde max antal pr. kolonne. Hvis antallet er 1 eller 2 er det naturvis i 1 eller 2 kolonner.
firstChar="" antalRows=0 for i = lbound(ordArr) to ubound(ordArr) if firstChar <> ucase(left(ordArr(i),1)) then if antalRows > 0 then Response.Write "</tr></table>" Response.Write "</tr>" antalRows = 0 end if if firstChar <> "" then Response.Write "<tr><td colspan=""" & maxPrRow & """> </td></tr>" firstChar = ucase(left(ordArr(i),1)) Response.Write "<tr><td colspan=""" & maxPrRow & """>" & firstChar & "</td></tr>" Response.Write "<tr>" antalKarakter = countChar(ordArr,firstChar) antalPrKol=abs(int(-antalKarakter/maxPrRow)) end if
if antalRows=0 then Response.Write "<td valign=""top""><table>" end if
antalRows=antalRows+1 if antalRows=antalPrKol then Response.Write "</table></td>" antalRows=0 end if
Next if ordPrCol > 0 then Response.Write "</tr>" %> </table>
</body> </html>
<% Function Sorter(ByVal tabel) Dim blnContinue, i, varFirst, varSecond blnContinue = True Do Until blnContinue = False blnContinue = False For i = 0 to UBound(tabel) If i = UBound(tabel) Then Exit For Arr = Split(tabel(i),".") tmp1 = arr(0) if isnumeric(tmp1) then tmp1 = Int(tmp1) Arr = Split(tabel(i+1),".") tmp2 = arr(0) if isnumeric(tmp2) then tmp2 = Int(tmp2) If tmp1 > tmp2 Then varFirst = tabel(i) varSecond = tabel(i+1) tabel(i) = varSecond tabel(i+1) = varFirst blnContinue = True End If Next Loop Sorter = tabel End Function
Function countChar(tabel,char) dim x antal=0 for x=lbound(tabel) to ubound(tabel) if ucase(char)=ucase(left(tabel(x),1)) then antal=antal+1 end if next countChar=antal End function
Skal det være sådan der er 4 også når antallet er imellem 5 og 9 så kan det laves sådan her:
<html> <body>
<% ordArr = Split("a1,b1,a2,a8,a4,b4,b3,a3,a5,a7,b7,b6,c1,c2,c3,c4,c5,c6,d1,d2,a10,a11,a12,a13,a14,a15,a16,a17,a18,a19,a20,a21,a22,e1,e2,e3,e4,e5,e6,e7,e8,e9,e10",",") ordArr = Sorter(ordArr) %> <table width="100%"> <% ordPrCol = 0 maxPrRow = 4 nrCol = 0 firstChar="" antalRows=0 for i = lbound(ordArr) to ubound(ordArr)
if firstChar <> ucase(left(ordArr(i),1)) then if antalRows > 0 then Response.Write "</tr></table>" Response.Write "</tr>" antalRows = 0 end if nrCol=0 firsteHasMax=false if firstChar <> "" then Response.Write "<tr><td colspan=""" & maxPrRow & """> </td></tr>" firstChar = ucase(left(ordArr(i),1)) Response.Write "<tr><td colspan=""" & maxPrRow & """>" & firstChar & "</td></tr>" Response.Write "<tr>" antalKarakter = countChar(ordArr,firstChar) antalPrKol=abs(int(-antalKarakter/maxPrRow)) if (antalPrKol*maxPrRow - antalKarakter >= antalPrKol) and (antalPrKol>1) then firsteHasMax=true end if end if
if antalRows=0 then Response.Write "<td valign=""top""><table>" end if
antalRows=antalRows+1 if antalRows=antalPrKol then Response.Write "</table></td>" antalRows=0 nrCol=nrCol+1 if firsteHasMax=true then if (antalPrKol*nrCol+(antalPrKol-1)*(maxPrRow-nrCol)) >= antalKarakter then firsteHasMax=false antalPrKol=antalPrKol-1 end if end if end if
Next if ordPrCol > 0 then Response.Write "</tr>" %> </table>
</body> </html>
<% Function Sorter(ByVal tabel) Dim blnContinue, i, varFirst, varSecond blnContinue = True Do Until blnContinue = False blnContinue = False For i = 0 to UBound(tabel) If i = UBound(tabel) Then Exit For Arr = Split(tabel(i),".") tmp1 = arr(0) if isnumeric(tmp1) then tmp1 = Int(tmp1) Arr = Split(tabel(i+1),".") tmp2 = arr(0) if isnumeric(tmp2) then tmp2 = Int(tmp2) If tmp1 > tmp2 Then varFirst = tabel(i) varSecond = tabel(i+1) tabel(i) = varSecond tabel(i+1) = varFirst blnContinue = True End If Next Loop Sorter = tabel End Function
Function countChar(tabel,char) dim x antal=0 for x=lbound(tabel) to ubound(tabel) if ucase(char)=ucase(left(tabel(x),1)) then antal=antal+1 end if next countChar=antal End function
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