vise 3 billeder

noget ala:
-----
$count = 0;
echo "<table>";
while ($row = mysql_fecth_array($result)){
if ($count == 0){
  echo "<tr>";
}
echo "<td>$row['filnavn']<td>";
$count++;
if ($count == 2){
  echo "</tr>";
  $count = 0;
}
}
echo "</table>";

$query = .........henter billeder..............

$antal = mysql_num_rows($query);
echo"<table><tr>\n";
$i = 0;

while($row = mysql_fetch_array($query)) {
$i++;
echo"    <td><img src=\"$row["billede"]\"></td>\n";

if($i%$antal == 0 && $i != $antal) {
echo"</tr><tr>\n";
}

}
echo"</tr></table>";

Hov!

busschou virker fint smidt et svar...

oki doki... :o)

$query = .........henter billeder..............

$antal = mysql_num_rows($query);
echo"<table><tr>\n";
$i = 0;

while($row = mysql_fetch_array($query)) {
$i++;
echo"    <td><img src=\"$row["billede"]\"></td>\n";

if($i%$3 == 0 && $i != $antal) {
echo"</tr><tr>\n";
}

}
echo"</tr></table>";

:O)