Kun 1 bruger per brugernavn

Hej Eksperter.

Jeg har den her kode, hvor jeg lige har sat et if statement ind, og et else i bunden, som gerne skulle gå ind og sikre at der ikke bliver oprettet 2 brugere med samme navn, men den bliver ved med at komme med denne error:

"Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ',' or ';' in /home/virtual/xsix.dk/public_html/onlineny/human.php on line 90"

Nogen der kan se hvad der er galt?

<?php
            require_once('connect.php');
$playernames = mysql_query("SELECT accountname FROM players") or die(mysql_error());
$playernames_data = mysql_fetch_array($playernames);
    if($_POST["name"] != playernames_data) {
    if (isset($_POST['submitBtn'])) {
        $name    = (isset($_POST['name'])) ? addslashes(htmlentities($_POST['name'])) : '' ;
        $pass  = (isset($_POST['pass'])) ? addslashes(htmlentities($_POST['pass'])) : '' ;
        $email  = (isset($_POST['email'])) ? addslashes(htmlentities($_POST['email'])) : '' ;
        $usertype  = "User";
        $race  = "Human";
        $str  = "8";
        $agi  = "8";
        $sta  = "8";
        $ing  = "8";
        $dex  = "8";
        $attackspeed  = "1.8";
        $dodgechance  = "0.8";
        $hitchance  = "88";
        $money  = "100";
        $maxhp  = "80";
        $currenthp  = "80";
        $maxmana  = "80";
        $currentmana  = "80";
        $level  = "1";
        $weaponname  = "None";       
        $armorname  = "None";

        //Minimum name and comment length.
        if ((strlen($name) > 3)){
            $sql = "INSERT INTO players (accountname,accountpass,email,usertype,race,str,agi,sta,ing,dex,attackspeed,dodgechance,hitchance,money,maxhp,currenthp,maxmana,currentmana,level,weaponname) VALUES (";
            $sql .= "'".$name."','".$pass."','".$email."','".$usertype."','".$race."','".$str."','".$agi."','".$sta."','".$ing."','".$dex."','".$attackspeed."','".$dodgechance."','".$hitchance."','".$money."','".$maxhp."','".$currenthp."','".$maxmana."','".$currentmana."','".$level."','".$weaponname."')";
            mysql_query($sql) or die(mysql_error());
        }
       
        header("Location: index.php");
    }
    else {

?>

  </font>
            <p>
            <img src="gfx/human.gif">

 
  </p>

 
  <form action="human.php" method="post" name="human">
    <table>
      <tr><th>Account Name:</th><td><input name="name" /></td></tr>
      <tr><th>Account Password:</th><td><input type="password" name="pass" /></td></tr>
      <tr><th>Email:</th><td><input name="email" /></td></tr>
      <td><input type="submit" name="submitBtn" value="Register"/></td>
    </table> 
</form>
<?php } ?>

<?php
}
else
{
echo "A user already excist with the accountname: " . $_POST[name]";
exit();
}
  ?>  </p></td>


På forhånd tak,

Mvh.
XsiX