hvad er der galt?

$connection = mysql_connect($sql_host,$sql_user,$sql_passwd);

$db = mysql_select_db(\"dbh\", $connection);

$sql = \"SELECT id, name, rank, password, race, realname, age, city, icq, email, homepage, con, info FROM members WHERE name = \'$name\' ORDER BY id ASC\";

$sql_result = mysql_query($sql,$connection);

while ($row = mysql_fetch_array($sql_result)) {
$id = $row[\"id\"];
$name = $row[\"name\"];
$rank = $row[\"rank\"];
$password = $row[\"password\"];
$race = $row[\"race\"];
$realname = $row[\"realname\"];
$age = $row[\"age\"];
$city = $row[\"city\"];
$icq = $row[\"icq\"];
$email = $row[\"email\"];
$homepage = $row[\"homepage\"];
$con = $row[\"con\"];
$info = $row[\"info\"];
echo \"</table>
<center>$name\'s info.</center>
<table width=\\\"300\\\" border=\\\"0\\\" cellpadding=\\\"0\\\" cellspacing=\\\"0\\\" align=\\\"center\\\">
  <tr>
  <td width=\\\"100\\\" height=\\\"18\\\">Navn:</td><td width=\\\"200\\\">$realname</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">Yndlig race:</td><td>$race</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">Alder:</td><td>$age</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">By:</td><td>$city</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">Icq:</td><td>$icq</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">E-mail:</td><td>$email</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">Hjemmeside:</td><td>$homepage</td>
  </tr>
  <tr>
  <td height=\\\"18\\\">Forbindelse:</td><td>$forbindelse</td>
  </tr>
  <tr>
  <td valign=\\\"top\\\" height=\\\"18\\\">Info:</td><td>$info</td>
  </tr>
</table>\";
}
mysql_close();

Når jeg køre det her script så får jeg fejlen:
Warning: Supplied argument is not a valid MySQL result resource in d:\\apache\\htdocs\\members.php on line 111