OpenFile dialogboks i Access 2000

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Private Type OPENFILENAME
    lStructSize As Long
    hwndOwner As Long
    hInstance As Long
    lpstrFilter As String
    lpstrCustomFilter As String
    nMaxCustFilter As Long
    nFilterIndex As Long
    lpstrFile As String
    nMaxFile As Long
    lpstrFileTitle As String
    nMaxFileTitle As Long
    lpstrInitialDir As String
    lpstrTitle As String
    Flags As Long
    nFileOffset As Integer
    nFileExtension As Integer
    lpstrDefExt As String
    lCustData As Long
    lpfnHook As Long
    lpTemplateName As String
End Type

Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As OPENFILENAME) As Long


Function SimpleGetOpenFileName() As String
' Opens the Open dialog with default values.

    Dim msaof As OPENFILENAME
    Dim intRet As Integer
    Dim strRet As String
      'initialize sensible fields of OPENFILENAME
  With msaof
      .lStructSize = Len(msaof)
      .lpstrTitle = "Select Any File"
      .lpstrFilter = "All Files" & vbNullChar & "*.*" & vbNullChar & vbNullChar
      .lpstrFile = String$(255, 0)
      .nMaxFile = 255
  End With

   
    intRet = GetOpenFileName(msaof)
    If intRet Then
        strRet = msaof.lpstrFile
    End If
   
    SimpleGetOpenFileName = strRet
End Function

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Det virker :-)

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