Omskrivning af popup()

ligemeget. Jeg fik det til at virker

Du har sikkert kløjs i, at der ikke var {} om det ...

Men behold du dine points her, jeg fik jo faktisk for mange i det andet spørgsmål !-)

function popup(obj,obj1,obj2) {
  if (document.getElementById) {
    if (document.getElementById(obj).style.visibility == 'visible'){
      document.getElementById(obj).style.visibility = 'hidden';
      document.getElementById(obj1).style.visibility = 'hidden';
      document.getElementById(obj2).style.visibility = 'visible';
    }else{
      document.getElementById(obj).style.visibility = 'visible';
      document.getElementById(obj1).style.visibility = 'hidden';
      document.getElementById(obj2).style.visibility = 'hidden';
    }
  }

  else if (document.layers && document.layers[obj] != null) {
    if (document.layers[obj].visibility == 'visible' ||
        document.layers[obj].visibility == 'show' ){
      document.layers[obj].visibility = 'hidden';
      document.layers[obj1].visibility = 'hidden';
      document.layers[obj2].visibility = 'visible';
    }else{
      document.layers[obj].visibility = 'visible';
      document.layers[obj1].visibility = 'hidden';
      document.layers[obj2].visibility = 'hidden';
    }
  }

  else if (document.all) {
    if (document.all[obj].style.visibility == 'visible'){
      document.all[obj].style.visibility = 'hidden';
      document.all[obj1].style.visibility = 'hidden';
      document.all[obj2].style.visibility = 'visible';
    }else{
      document.all[obj].style.visibility = 'visible';
      document.all[obj1].style.visibility = 'hidden';
      document.all[obj2].style.visibility = 'hidden';
    }
  }

  return false;
}

*lol*

-- så lige pludselig, at du havde klaret den !-)

hehe.