find top level domain i et link evt .dk eller .com

$url=parse_url(http://www.exp.dk/test.php?csel=br);

$url[scheme] = http
$url[host] = www.exp.dk
$url[path] = /test.php
$url[query] = csel=br

burde vel kunne gøre det

eller måske:

echo preg_replace("/^(http:\/\/[^\/]*).*/i","$1",$fullurl);

skal kun bruge evt .dk eller .com fra domænet

Du kan tage et kig her hvis du vil have alt info ud. samt om det er et .dk, .com, .net osv:

<?php
function parseUrl($url) {
    $r  = "^(?:(?P<scheme>\w+)://)?";
    $r .= "(?:(?P<login>\w+):(?P<pass>\w+)@)?";
    $r .= "(?P<host>(?:(?P<subdomain>[\w\.]+)\.)?" . "(?P<domain>\w+\.(?P<extension>\w+)))";
    $r .= "(?::(?P<port>\d+))?";
    $r .= "(?P<path>[\w/]*/(?P<file>\w+(?:\.\w+)?)?)?";
    $r .= "(?:\?(?P<arg>[\w=&]+))?";
    $r .= "(?:#(?P<anchor>\w+))?";
    $r = "!$r!";                                                // Delimiters
   
    preg_match ( $r, $url, $out );
   
    return $out;
}
print_r ( parseUrl ( 'me:you@sub.site.org:29000/pear/validate.html?happy=me&sad=you#url' ) );
?>

This returns:
Array
(
    [0] => me:you@sub.site.org:29000/pear/validate.html?happy=me&sad=you#url
    [scheme] =>
    [1] =>
    [login] => me
    [2] => me
    [pass] => you
    [3] => you
    [host] => sub.site.org
    [4] => sub.site.org
    [subdomain] => sub
    [5] => sub
    [domain] => site.org
    [6] => site.org
    [extension] => org
    [7] => org
    [port] => 29000
    [8] => 29000
    [path] => /pear/validate.html
    [9] => /pear/validate.html
    [file] => validate.html
    [10] => validate.html
    [arg] => happy=me&sad=you
    [11] => happy=me&sad=you
    [anchor] => url
    [12] => url
)

Hvad med http://www.sub.test.co.uk/ ???