Avatar billede west Nybegynder
22. september 2002 - 22:38 Der er 10 kommentarer og
1 løsning

det indtastede SKAL være email adresse

kan dette laves så den sikrer at det er en emailadresse
(skal indeholde @)

if ( frm.d.value.length == 0 ) {
        alert( "der skal skrives noget i d feltet." );
        return false;
    }

??????????
Avatar billede medions Nybegynder
22. september 2002 - 22:44 #1
brug Reg Xp:

var pattern = new RegExp(\"^.+@.+\\..{2,4}$\");

//>Rune
Avatar billede west Nybegynder
22. september 2002 - 22:45 #2
hvordan skal der stå helt nøjagtigt ?
Avatar billede medions Nybegynder
22. september 2002 - 22:46 #3
<SCRIPT language=JavaScript1.2>
  var x = "jni@omnix.dk";
  var pattern = new RegExp(\"^.+@.+\\..{2,4}$\");
  var tjek = x.match( pattern );
  var y = tjek.length;
  document.write(y+"<br>");
  document.write(tjek[0]);
</SCRIPT>

//>Rune
Avatar billede medions Nybegynder
22. september 2002 - 22:48 #4
Men til det du har der skal du nok bruge denne:

if ( feltverdi.indexOF( "@" ) > 0 ) {
    // fint nok der er mindst eet '@' tegn i det felt
} else {
    alert( "Felter er forkert udfyldt.\nDer skal være '@' i en emailadrese." );
}

//>Rune
Avatar billede Slettet bruger
22. september 2002 - 22:51 #5
<script>
function emailCheck (emailStr) {

/* The following variable tells the rest of the function whether or not
to verify that the address ends in a two-letter country or well-known
TLD.  1 means check it, 0 means don't. */

var checkTLD=1;

/* The following is the list of known TLDs that an e-mail address must end with. */

var knownDomsPat=/^(com|net|org|edu|int|mil|gov|arpa|biz|aero|name|coop|info|pro|museum)$/;

/* The following pattern is used to check if the entered e-mail address
fits the user@domain format.  It also is used to separate the username
from the domain. */

var emailPat=/^(.+)@(.+)$/;

/* The following string represents the pattern for matching all special
characters.  We don't want to allow special characters in the address.
These characters include ( ) < > @ , ; : \ " . [ ] */

var specialChars="\\(\\)><@,;:\\\\\\\"\\.\\[\\]";

/* The following string represents the range of characters allowed in a
username or domainname.  It really states which chars aren't allowed.*/

var validChars="\[^\\s" + specialChars + "\]";

/* The following pattern applies if the "user" is a quoted string (in
which case, there are no rules about which characters are allowed
and which aren't; anything goes).  E.g. "jiminy cricket"@disney.com
is a legal e-mail address. */

var quotedUser="(\"[^\"]*\")";

/* The following pattern applies for domains that are IP addresses,
rather than symbolic names.  E.g. joe@[123.124.233.4] is a legal
e-mail address. NOTE: The square brackets are required. */

var ipDomainPat=/^\[(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})\]$/;

/* The following string represents an atom (basically a series of non-special characters.) */

var atom=validChars + '+';

/* The following string represents one word in the typical username.
For example, in john.doe@somewhere.com, john and doe are words.
Basically, a word is either an atom or quoted string. */

var word="(" + atom + "|" + quotedUser + ")";

// The following pattern describes the structure of the user

var userPat=new RegExp("^" + word + "(\\." + word + ")*$");

/* The following pattern describes the structure of a normal symbolic
domain, as opposed to ipDomainPat, shown above. */

var domainPat=new RegExp("^" + atom + "(\\." + atom +")*$");

/* Finally, let's start trying to figure out if the supplied address is valid. */

/* Begin with the coarse pattern to simply break up user@domain into
different pieces that are easy to analyze. */

var matchArray=emailStr.match(emailPat);

if (matchArray==null) {

/* Too many/few @'s or something; basically, this address doesn't
even fit the general mould of a valid e-mail address. */

alert("Email address seems incorrect (check @ and .'s)");
return false;
}
var user=matchArray[1];
var domain=matchArray[2];

// Start by checking that only basic ASCII characters are in the strings (0-127).

for (i=0; i<user.length; i++) {
if (user.charCodeAt(i)>127) {
alert("Ths username contains invalid characters.");
return false;
  }
}
for (i=0; i<domain.length; i++) {
if (domain.charCodeAt(i)>127) {
alert("Ths domain name contains invalid characters.");
return false;
  }
}

// See if "user" is valid

if (user.match(userPat)==null) {

// user is not valid

alert("The username doesn't seem to be valid.");
return false;
}

/* if the e-mail address is at an IP address (as opposed to a symbolic
host name) make sure the IP address is valid. */

var IPArray=domain.match(ipDomainPat);
if (IPArray!=null) {

// this is an IP address

for (var i=1;i<=4;i++) {
if (IPArray[i]>255) {
alert("Destination IP address is invalid!");
return false;
  }
}
return true;
}

// Domain is symbolic name.  Check if it's valid.

var atomPat=new RegExp("^" + atom + "$");
var domArr=domain.split(".");
var len=domArr.length;
for (i=0;i<len;i++) {
if (domArr[i].search(atomPat)==-1) {
alert("The domain name does not seem to be valid.");
return false;
  }
}

/* domain name seems valid, but now make sure that it ends in a
known top-level domain (like com, edu, gov) or a two-letter word,
representing country (uk, nl), and that there's a hostname preceding
the domain or country. */

if (checkTLD && domArr[domArr.length-1].length!=2 &&
domArr[domArr.length-1].search(knownDomsPat)==-1) {
alert("The address must end in a well-known domain or two letter " + "country.");
return false;
}

// Make sure there's a host name preceding the domain.

if (len<2) {
alert("This address is missing a hostname!");
return false;
}

// If we've gotten this far, everything's valid!
return true;
}

if (!emailCheck(f.besked.value)) return false;

return true;
}
</script>

skulle tjekke alt hvad der er at tjekke ved en amail adresse.

mvh.
Questis.dk
Avatar billede medions Nybegynder
22. september 2002 - 22:52 #6
Questis> LOL

//>Rune
Avatar billede Slettet bruger
22. september 2002 - 22:54 #7
eller er der glemt noget ? &:-)

tror det ikke
Avatar billede medions Nybegynder
22. september 2002 - 22:56 #8
*G* Nej tror jeg heller ik'! -Men det han ville var nu bare at tjekke om der fantes et snabela ;o)

//>Rune
Avatar billede Slettet bruger
22. september 2002 - 22:58 #9
nå for søren var vist lige hurtig nok der &:-)

så kan han nok godt undvære en lille smule af det kode stykker.
Avatar billede medions Nybegynder
22. september 2002 - 22:59 #10
lol ja

//>Rune
Avatar billede medions Nybegynder
05. december 2002 - 12:39 #11
Thx 4 Poinz

//>Rune
Avatar billede Ny bruger Nybegynder

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