At sende data i en form

Jeg har et problem med et lille test script jeg har lavet. Scriptet bliver ved med at vælge den samme post i en select box, selvom værdien har ændret sig. Min include fil ser sådan her ud:

<?php
function html_header($title) {
  print ("<HTML><HEAD><TITLE>$title</TITLE>");
  print ("<LINK TYPE=\"text/css\" REL=\"stylesheet\" HREF=\"php.css\">");
  print ("</HEAD><BODY>");
}

function html_buttom() {
  print ("</BODY></HTML>");
}

function display_selectbox($option) {
  $name = "bread";
  print ("<SELECT NAME='$name'>");
  print ("<OPTION>$option</OPTION>");
  print ("<OPTION VALUE='-'>    -</OPTION>");
  print ("<OPTION VALUE='Baking Bread'");
  if ($option = "Baking Bread") {
      print (" SELECTED>Baking Bread</OPTION>");
  } else {
      print (">Baking Bread</OPTION>");
  }
  print ("<OPTION VALUE='Baking Cookies'");
  if ($option = "Baking Cookies") {
      print (" SELECTED>Baking Cookies</OPTION>");
  } else {
      print (">Baking Cookies</OPTION>");
  }
  print ("</SELECT>");
}

?>

Filen sendingdata.php ser sådan her ud:

<?php

include("common.inc");
$title = "Sending data";
html_header($title);

print ("<TABLE><TR><TD><CENTER><H1>What are you baking now?<H1></CENTER></TD></TR>");
print ("<TR><TD>bread = $bread</TD></TR>");
print ("<TR><TD><CENTER><FORM ACTION='sendingdata.php' METHOD='POST' NAME='breadform'>");
print ("<BR><BR><H4>I am baking:&nbsp;&nbsp;&nbsp;&nbsp;</H4>");
$option = $bread;
display_selectbox($option);
print ("<BR><BR><INPUT TYPE='SUBMIT'>");
print ("</FORM></CENTER></TD></TR></TABLE>");

html_buttom();

?>

Hvad er der galt?