Excel ark oplåsning

Ja; men afhængig af, hvordan det er låst. Er det hele arket ? Er det VBA delen ? Eller ?

Det kan gøres med det korrekte software, som bestemmes ud fra, hvad der er låst 😊

Jeg har i gamle dage brugt denne formel, men virker ikke mere
på win 11 og nyeste excel

Sub PasswordBreaker()
'Knækker arkbeskyttelse.
  Dim i As Integer, j As Integer, k As Integer
  Dim L As Integer, m As Integer, n As Integer
  Dim i1 As Integer, i2 As Integer, i3 As Integer
  Dim i4 As Integer, i5 As Integer, i6 As Integer
  On Error Resume Next
    For i = 65 To 66
      For j = 65 To 66
        For k = 65 To 66
          For L = 65 To 66
            For m = 65 To 66
              For i1 = 65 To 66
                For i2 = 65 To 66
                  For i3 = 65 To 66
                    For i4 = 65 To 66
                      For i5 = 65 To 66
                        For i6 = 65 To 66
                          For n = 32 To 126
                            ActiveSheet.Unprotect Chr(i) & Chr(j) & Chr(k) & _
                            Chr(L) & Chr(m) & Chr(i1) & Chr(i2) & Chr(i3) & _
                            Chr(i4) & Chr(i5) & Chr(i6) & Chr(n)
                            If ActiveSheet.ProtectContents = False Then
          MsgBox "Koden er brudt og dokumenet kan nu rettes!", vbExclamation + vbOKOnly
                              Exit Sub
                            End If
                          Next
                        Next
                      Next
                    Next
                  Next
                Next
              Next
            Next
          Next
        Next
      Next
    Next
End Sub

Du kan prøve her :

https://tools.pdf24.org/da/las-op-for-pdf

#3 - Og hvad har det link med Excel at gøre ?

#4 Sorry - fejl 40 i morgen-hovedet *S*

Check lige denne video :
https://youtu.be/2x23vZIRYRs?si=dLSXWqVjHshSRaBz
Det virker !

Mvh martens

#6 - Dette er ikke en metode man skal rode sig ud i, hvis ikke man har fuld styr på brugen af Hex editor.
Desuden så virker det ikke på Excel filer som er baseret på f.eks. Excel 365.

Jeg fandt denne for noget tid siden. Den virker upåklageligt:
Sub RemoveProtection()

Dim dialogBox As FileDialog
Dim sourceFullName As String
Dim sourceFilePath As String
Dim sourceFileName As String
Dim sourceFileType As String
Dim newFileName As Variant
Dim tempFileName As String
Dim zipFilePath As Variant
Dim oApp As Object
Dim FSO As Object
Dim xmlSheetFile As String
Dim xmlFile As Integer
Dim xmlFileContent As String
Dim xmlStartProtectionCode As Double
Dim xmlEndProtectionCode As Double
Dim xmlProtectionString As String

'Open dialog box to select a file
Set dialogBox = Application.FileDialog(msoFileDialogFilePicker)
dialogBox.AllowMultiSelect = False
dialogBox.Title = "Select file to remove protection from"

If dialogBox.Show = -1 Then
    sourceFullName = dialogBox.SelectedItems(1)
Else
    Exit Sub
End If

'Get folder path, file type and file name from the sourceFullName
sourceFilePath = Left(sourceFullName, InStrRev(sourceFullName, "\"))
sourceFileType = Mid(sourceFullName, InStrRev(sourceFullName, ".") + 1)
sourceFileName = Mid(sourceFullName, Len(sourceFilePath) + 1)
sourceFileName = Left(sourceFileName, InStrRev(sourceFileName, ".") - 1)

'Use the date and time to create a unique file name
tempFileName = "Temp" & Format(Now, " dd-mmm-yy h-mm-ss")

'Copy and rename original file to a zip file with a unique name
newFileName = sourceFilePath & tempFileName & ".zip"
On Error Resume Next
FileCopy sourceFullName, newFileName

If Err.Number <> 0 Then
    MsgBox "Unable to copy " & sourceFullName & vbNewLine _
        & "Check the file is closed and try again"
    Exit Sub
End If
On Error GoTo 0

'Create folder to unzip to
zipFilePath = sourceFilePath & tempFileName & "\"
MkDir zipFilePath

'Extract the files into the newly created folder
Set oApp = CreateObject("Shell.Application")
oApp.Namespace(zipFilePath).CopyHere oApp.Namespace(newFileName).items

'loop through each file in the \xl\worksheets folder of the unzipped file
xmlSheetFile = Dir(zipFilePath & "\xl\worksheets\*.xml*")
Do While xmlSheetFile <> ""

    'Read text of the file to a variable
    xmlFile = FreeFile
    Open zipFilePath & "xl\worksheets\" & xmlSheetFile For Input As xmlFile
    xmlFileContent = Input(LOF(xmlFile), xmlFile)
    Close xmlFile

    'Manipulate the text in the file
    xmlStartProtectionCode = 0
    xmlStartProtectionCode = InStr(1, xmlFileContent, "<sheetProtection")

    If xmlStartProtectionCode > 0 Then

        xmlEndProtectionCode = InStr(xmlStartProtectionCode, _
            xmlFileContent, "/>") + 2 '"/>" is 2 characters long
        xmlProtectionString = Mid(xmlFileContent, xmlStartProtectionCode, _
            xmlEndProtectionCode - xmlStartProtectionCode)
        xmlFileContent = Replace(xmlFileContent, xmlProtectionString, "")

    End If

    'Output the text of the variable to the file
    xmlFile = FreeFile
    Open zipFilePath & "xl\worksheets\" & xmlSheetFile For Output As xmlFile
    Print #xmlFile, xmlFileContent
    Close xmlFile

    'Loop to next xmlFile in directory
    xmlSheetFile = Dir

Loop

'Read text of the xl\workbook.xml file to a variable
xmlFile = FreeFile
Open zipFilePath & "xl\workbook.xml" For Input As xmlFile
xmlFileContent = Input(LOF(xmlFile), xmlFile)
Close xmlFile

'Manipulate the text in the file to remove the workbook protection
xmlStartProtectionCode = 0
xmlStartProtectionCode = InStr(1, xmlFileContent, "<workbookProtection")
If xmlStartProtectionCode > 0 Then

    xmlEndProtectionCode = InStr(xmlStartProtectionCode, _
        xmlFileContent, "/>") + 2 ''"/>" is 2 characters long
    xmlProtectionString = Mid(xmlFileContent, xmlStartProtectionCode, _
        xmlEndProtectionCode - xmlStartProtectionCode)
    xmlFileContent = Replace(xmlFileContent, xmlProtectionString, "")

End If

'Manipulate the text in the file to remove the modify password
xmlStartProtectionCode = 0
xmlStartProtectionCode = InStr(1, xmlFileContent, "<fileSharing")
If xmlStartProtectionCode > 0 Then

    xmlEndProtectionCode = InStr(xmlStartProtectionCode, xmlFileContent, _
        "/>") + 2 ''"/>" is 2 characters long
    xmlProtectionString = Mid(xmlFileContent, xmlStartProtectionCode, _
        xmlEndProtectionCode - xmlStartProtectionCode)
    xmlFileContent = Replace(xmlFileContent, xmlProtectionString, "")

End If

'Output the text of the variable to the file
xmlFile = FreeFile
Open zipFilePath & "xl\workbook.xml" & xmlSheetFile For Output As xmlFile
Print #xmlFile, xmlFileContent
Close xmlFile

'Create empty Zip File
Open sourceFilePath & tempFileName & ".zip" For Output As #1
Print #1, Chr$(80) & Chr$(75) & Chr$(5) & Chr$(6) & String(18, 0)
Close #1

'Move files into the zip file
oApp.Namespace(sourceFilePath & tempFileName & ".zip").CopyHere _
oApp.Namespace(zipFilePath).items
'Keep script waiting until Compressing is done
On Error Resume Next
Do Until oApp.Namespace(sourceFilePath & tempFileName & ".zip").items.Count = _
    oApp.Namespace(zipFilePath).items.Count
    Application.Wait (Now + TimeValue("0:00:01"))
Loop
On Error GoTo 0

'Delete the files & folders created during the sub
Set FSO = CreateObject("scripting.filesystemobject")
FSO.deletefolder sourceFilePath & tempFileName

'Rename the final file back to an xlsx file
Name sourceFilePath & tempFileName & ".zip" As sourceFilePath & sourceFileName _
& "_" & Format(Now, "dd-mmm-yy h-mm-ss") & "." & sourceFileType

'Show message box
MsgBox "The workbook and worksheet protection passwords have been removed.", _
vbInformation + vbOKOnly, Title:="Password protection"

End Sub

Tak for jeres input, lukker tråden,
fik det ikke til at virke