Java and XML

if you want
<a>
<b>1</b>
<b>2</b>
<b>stuff</b>
</a>

can\'t you just read in the structure line by line, and add the line
<b>stuff</b>
when you\'re in the right position?

Hello!

How do you do that? Sounds really interesting.
I use org.w3c.dom for this.

So far I read a empty xml-skeleton like this:
<a>
<b></b>
<b></b>
<a>

Load it into a Document like:
FileInputStream is = new FileInputStream(_skeletonFile);
Parser parser = new Parser(_skeletonFile.getPath());
_document = parser.readStream(is);

So how do I now add a third <b> element dynamically?

I set a value into a object with:
    protected void setFieldvalue(String nodeName, String value)
    {
NodeList nodeList = _document.getElementsByTagName(nodeName);
Element node = (Element) nodeList.item(0);

NodeList children = node.getChildNodes();
children.item(0).setNodeValue(value);
}

So far the method above only work if the node name is unique.

If you use java.io.RandomAccessFile, you can read a line at a time with:

String currentLine = RAF.readLine();//Reads the next line of text from this file.

once you fine the right line, insert your text into the file with
RAF.writeChars(String newLine);//Writes a string to the file as a sequence of characters.

It _should_ work, but I\'m not promising anything :-).

Okey, but unfortunately it is to late to do the dynamic part skeleton at file-level. I need to do this with xml in the Document.

I take it you have the entire skeleton as a single string. If you used java.util.StringTokenizer you could split the skeleton-string into several strings with

tokenizer = java.util.StringTokenizer.StringTokenizer(String string, String deliminator)

Setting the deliminator as \"\\r\\n\" (carrige return + new line) should split the skeleton into lines.

String skeletonLine = tokenizer.nextToken()

will then return the next line in the skeleton. When you change the structure of the skeleton, you can just warp it into a single string again, and then pass it through the tokenizer again.

Or when you open the skeleton the first time, you could store it like a string-array or in a vector, with a single string per line. A linked list could work as well. It all depends on the speed at wich you want it to work.

You can create the element yourself by using
Element bTag = document.createElement(\"b\");
Element data = document.createCDATASection(\"someText\");
bTag.appendChild(data);

Then you can append it to the document by using
document.appendChild(bTag);

Hello!
Thanks for all your help, I solved it like this:
document.getElementsByTagName(nodeName).item(0).appendChild(node);

Best regards

Fredrik

lbhansen - jeg laver lige et spørgsmål til 80 points, så du kan få dine points:

http://www.eksperten.dk/spm/138745

fredand - you should have asked lbhansen to leave an answer instead of a comment, so he could have gotten the points instead of me. My answer wasn\'t used, hence I shouldn\'t get any points for it.

OK!
But thanks for your time any way!!