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guzzie Nybegynder

01. januar 2001 - 15:43 Der er 21 kommentarer og
1 løsning

upload script

hi there

I have an upload script that i use and it works great.
however does anybody know if it is possible that I can choose where I upload to when i am uploading?
Something like when i click on \"upload\" i can choose which folder/map on my server it gets uploaded to

Guzzie(fra England)

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netsrac Praktikant

01. januar 2001 - 15:47 #1

That might be possible.

Which script do you use to upload ?

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smurfen Nybegynder

01. januar 2001 - 16:14 #2

you\'ll have to choose it before you upload and store it in a session variable because of the method used to transfer files via forms.. but you could do it.. :)

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netsrac Praktikant

01. januar 2001 - 16:29 #3

Smurfen >> You can also tranfer data in a multipart form, it can be choosen where to place the upload at the same time as uploading.

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nomiz Nybegynder

01. januar 2001 - 16:31 #4

Hvad med at lave eksperten.com på engelsk.. ? - Store penge, venner.. Store penge

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netsrac Praktikant

01. januar 2001 - 16:33 #5

Så skal den jo nok hedde,

Theexpert.com

eller

Theexperts.com

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guzzie Nybegynder

01. januar 2001 - 16:45 #6

Heh :)
I do read Danish but my written Danish sucks a little :)
/netsrac
Ok I use the basic upload script from www.azero.dk
site and have changed it a little so that I use cases instead of rediecting to another page
I just use the script for testing purposes and it is out of interest i thought that it could maybe be done ????
Ideas anyone

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netsrac Praktikant

01. januar 2001 - 16:49 #7

Put in a text field and then it works, like this:

<html>
<body>

<form method=\"post\" enctype=\"multipart/form-data\" action=\"uploaded.asp\">
<input type=\"text\" name=\"uploadpath\">
<input type=file name=\"file1\"><br>
<input type=file name=\"file2\"><br>
<input type=file name=\"file3\"><br>
<input type=submit value=\"upload!\">
</form>

</body>
</html>

<html>
<body>
<%
Set Upload = Server.CreateObject(\"Persits.Upload.1\")
uploadpath = upload.form(\"uploadpath\")
Count = Upload.Save(uploadpath)
Response.Write Count & \" fil(er) modtaget.\"
%>
</body>
</html>

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guzzie Nybegynder

01. januar 2001 - 17:10 #8

/netsrac

hey there:)

I tried that the server chewed on it a few seconds then i got an error message
this is the script as it stands now

I tried what you said but just got the error ;(

<%Case \"1\"%>
<table width=\"100%\" align=\"left\"><tr><td align=\"left\">
Directory: http://www.guzzie.dk/www/upload_asp/upload/...
<form method=\"post\" enctype=\"multipart/form-data\" action=\"upload.asp?sample=2\">
<input type=file name=\"file1\"><br>
<input type=file name=\"file2\"><br>
<input type=file name=\"file3\"><br>
<input type=submit value=\"upload\">
</form>
</td></tr></table>
<%Case \"2\"%>

<%
Set Upload = Server.CreateObject(\"Persits.Upload.1\")
Count = Upload.Save(\"d:\\home\\guzziedk\\www\\upload_asp\\upload\")
Response.Write Count & \" fil(er) modtaget.\"
%>

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netsrac Praktikant

01. januar 2001 - 17:13 #9

What error message ?

You wrote the path on the server right ? not an http path ?

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guzzie Nybegynder

01. januar 2001 - 17:20 #10

Hello :)
yep i tested with this path
d:\\home\\guzziedk\\www\\upload_asp\\upload

can you verify this part im not an expert so can you tell me where this

uploadpath = upload.form(\"uploadpath\")

should go in this script
<%
Set Upload = Server.CreateObject(\"Persits.Upload.1\")
Count = Upload.Save(\"d:\\home\\guzziedk\\www\\upload_asp\\upload\")
Response.Write Count & \" fil(er) modtaget.\"
%>

:)guzzie

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netsrac Praktikant

01. januar 2001 - 17:24 #11

if you use this:
<%
Set Upload = Server.CreateObject(\"Persits.Upload.1\")
uploadpath = upload.form(\"uploadpath\")
Count = Upload.Save(uploadpath)
Response.Write Count & \" fil(er) modtaget.\"
%>
and make an text field in your upload form where you give the path where to save then i should upload without errors.

If not then copy & paste the error message here :-)

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guzzie Nybegynder

01. januar 2001 - 17:30 #12

this is the script now

<%Case \"1\"%>
<table width=\"100%\" align=\"left\"><tr><td align=\"left\">
Directory: http://www.guzzie.dk/www/upload_asp/upload/...
<form method=\"post\" enctype=\"multipart/form-data\" action=\"upload.asp?sample=2\">
<input type=\"text\" name=\"uploadpath\">
<input type=file name=\"file1\"><br>
<input type=file name=\"file2\"><br>
<input type=file name=\"file3\"><br>
<input type=submit value=\"upload\">
</form>
</td></tr></table>
<%Case \"2\"%>

<%
Set Upload = Server.CreateObject(\"Persits.Upload.1\")
uploadpath = upload.form(\"uploadpath\")
Count = Upload.Save(uploadpath)
Response.Write Count & \" fil(er) modtaget.\"
%>

and this is the error message

Persits.Upload.1 error \'800a0005\'

Access is denied.

/upload_asp/upload.asp, line 36

this is the address of the page
http://www.guzzie.dk/upload_asp/upload.asp?sample=1

;) sniff

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netsrac Praktikant

01. januar 2001 - 17:33 #13

Aha....Access is denied, that is because you do not have rights to upload pictures.
I use azero.dk myself, you shall use there support formular and ask for acces til uploading pictures.
Support Formular:
http://www.azero.dk/default.asp?/support/formular/

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guzzie Nybegynder

01. januar 2001 - 17:38 #14

hi again :)

I wrote to them a while ago and got rights
and have been using this script to upload all sorts of files and pictures for a few weeks now so i doubt it is that
the script works fine
hmmmm
u can see here
http://www.guzzie.dk/upload_asp/upload.asp?sample=3
this works fine
;) sniff, sniff

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netsrac Praktikant

01. januar 2001 - 17:40 #15

Just a secund, i will test myself :-)

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guzzie Nybegynder

01. januar 2001 - 17:50 #16

I put the points up to 150 ;0

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netsrac Praktikant

01. januar 2001 - 17:58 #17

I think i have an usefull solution now:

Make an tmp directery save the files here and then move them to the selected directory.
like this:

Set Upload = Server.CreateObject(\"Persits.Upload.1\")
Count = Upload.Save(\"d:\\home\\guzziedk\\www\\upload_asp\\upload\\tmp\")
uploadpath = upload.form(\"uploadpath\")
File.Copy uploadpath & File.ExtractFileName
File.Delete

Response.Write Count & \" fil(er) modtaget.\"

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guzzie Nybegynder

01. januar 2001 - 18:05 #18

hey again :)

i tried this it doesnt work either ;(
by tmp you mean a map that is called tmp?
if this is so then it doesnt work
;) sniff sniff

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netsrac Praktikant

01. januar 2001 - 18:09 #19

yes i mean make an map called tmp under the map
d:\\home\\guzziedk\\www\\upload_asp\\upload\\

There was an error in the script, this should work :-)

Set Upload = Server.CreateObject(\"Persits.Upload.1\")
Count = Upload.Save(\"D:\\home\\cnhdk\\www\\upload_test\\tmp\")
uploadpath = upload.form(\"uploadpath\")
For Each File in Upload.Files
File.Copy uploadpath & File.ExtractFileName
File.Delete
next

Response.Write Count & \" fil(er) modtaget.\"

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guzzie Nybegynder

01. januar 2001 - 18:23 #20

YEEHAAAAAA !!!!!!!!
many many thanks :)
u 1 cool dude :)
thank so much

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netsrac Praktikant

01. januar 2001 - 18:24 #21

No problem :-)

Thanks for the points :-)

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guzzie Nybegynder

01. januar 2001 - 18:26 #22

np :)

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Ny bruger Nybegynder

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